Integrand size = 22, antiderivative size = 61 \[ \int x \left (a^2+2 a b x+b^2 x^2\right )^{5/2} \, dx=-\frac {a (a+b x) \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{6 b^2}+\frac {\left (a^2+2 a b x+b^2 x^2\right )^{7/2}}{7 b^2} \]
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Time = 0.01 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {654, 623} \[ \int x \left (a^2+2 a b x+b^2 x^2\right )^{5/2} \, dx=\frac {\left (a^2+2 a b x+b^2 x^2\right )^{7/2}}{7 b^2}-\frac {a (a+b x) \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{6 b^2} \]
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Rule 623
Rule 654
Rubi steps \begin{align*} \text {integral}& = \frac {\left (a^2+2 a b x+b^2 x^2\right )^{7/2}}{7 b^2}-\frac {a \int \left (a^2+2 a b x+b^2 x^2\right )^{5/2} \, dx}{b} \\ & = -\frac {a (a+b x) \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{6 b^2}+\frac {\left (a^2+2 a b x+b^2 x^2\right )^{7/2}}{7 b^2} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(125\) vs. \(2(61)=122\).
Time = 1.03 (sec) , antiderivative size = 125, normalized size of antiderivative = 2.05 \[ \int x \left (a^2+2 a b x+b^2 x^2\right )^{5/2} \, dx=\frac {x^2 \left (21 a^5+70 a^4 b x+105 a^3 b^2 x^2+84 a^2 b^3 x^3+35 a b^4 x^4+6 b^5 x^5\right ) \left (\sqrt {a^2} b x+a \left (\sqrt {a^2}-\sqrt {(a+b x)^2}\right )\right )}{42 \left (-a^2-a b x+\sqrt {a^2} \sqrt {(a+b x)^2}\right )} \]
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Time = 2.16 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.21
method | result | size |
gosper | \(\frac {x^{2} \left (6 b^{5} x^{5}+35 a \,b^{4} x^{4}+84 a^{2} b^{3} x^{3}+105 a^{3} b^{2} x^{2}+70 a^{4} b x +21 a^{5}\right ) \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}}}{42 \left (b x +a \right )^{5}}\) | \(74\) |
default | \(\frac {x^{2} \left (6 b^{5} x^{5}+35 a \,b^{4} x^{4}+84 a^{2} b^{3} x^{3}+105 a^{3} b^{2} x^{2}+70 a^{4} b x +21 a^{5}\right ) \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}}}{42 \left (b x +a \right )^{5}}\) | \(74\) |
risch | \(\frac {\sqrt {\left (b x +a \right )^{2}}\, b^{5} x^{7}}{7 b x +7 a}+\frac {5 \sqrt {\left (b x +a \right )^{2}}\, a \,b^{4} x^{6}}{6 \left (b x +a \right )}+\frac {2 \sqrt {\left (b x +a \right )^{2}}\, a^{2} b^{3} x^{5}}{b x +a}+\frac {5 \sqrt {\left (b x +a \right )^{2}}\, a^{3} b^{2} x^{4}}{2 \left (b x +a \right )}+\frac {5 \sqrt {\left (b x +a \right )^{2}}\, a^{4} b \,x^{3}}{3 \left (b x +a \right )}+\frac {\sqrt {\left (b x +a \right )^{2}}\, a^{5} x^{2}}{2 b x +2 a}\) | \(154\) |
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Time = 0.24 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.93 \[ \int x \left (a^2+2 a b x+b^2 x^2\right )^{5/2} \, dx=\frac {1}{7} \, b^{5} x^{7} + \frac {5}{6} \, a b^{4} x^{6} + 2 \, a^{2} b^{3} x^{5} + \frac {5}{2} \, a^{3} b^{2} x^{4} + \frac {5}{3} \, a^{4} b x^{3} + \frac {1}{2} \, a^{5} x^{2} \]
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Leaf count of result is larger than twice the leaf count of optimal. 148 vs. \(2 (56) = 112\).
Time = 0.60 (sec) , antiderivative size = 148, normalized size of antiderivative = 2.43 \[ \int x \left (a^2+2 a b x+b^2 x^2\right )^{5/2} \, dx=\begin {cases} \sqrt {a^{2} + 2 a b x + b^{2} x^{2}} \left (- \frac {a^{6}}{42 b^{2}} + \frac {a^{5} x}{42 b} + \frac {10 a^{4} x^{2}}{21} + \frac {25 a^{3} b x^{3}}{21} + \frac {55 a^{2} b^{2} x^{4}}{42} + \frac {29 a b^{3} x^{5}}{42} + \frac {b^{4} x^{6}}{7}\right ) & \text {for}\: b^{2} \neq 0 \\\frac {- \frac {a^{2} \left (a^{2} + 2 a b x\right )^{\frac {7}{2}}}{7} + \frac {\left (a^{2} + 2 a b x\right )^{\frac {9}{2}}}{9}}{2 a^{2} b^{2}} & \text {for}\: a b \neq 0 \\\frac {x^{2} \left (a^{2}\right )^{\frac {5}{2}}}{2} & \text {otherwise} \end {cases} \]
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Time = 0.20 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.23 \[ \int x \left (a^2+2 a b x+b^2 x^2\right )^{5/2} \, dx=-\frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a x}{6 \, b} - \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a^{2}}{6 \, b^{2}} + \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}}}{7 \, b^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 107 vs. \(2 (53) = 106\).
Time = 0.27 (sec) , antiderivative size = 107, normalized size of antiderivative = 1.75 \[ \int x \left (a^2+2 a b x+b^2 x^2\right )^{5/2} \, dx=\frac {1}{7} \, b^{5} x^{7} \mathrm {sgn}\left (b x + a\right ) + \frac {5}{6} \, a b^{4} x^{6} \mathrm {sgn}\left (b x + a\right ) + 2 \, a^{2} b^{3} x^{5} \mathrm {sgn}\left (b x + a\right ) + \frac {5}{2} \, a^{3} b^{2} x^{4} \mathrm {sgn}\left (b x + a\right ) + \frac {5}{3} \, a^{4} b x^{3} \mathrm {sgn}\left (b x + a\right ) + \frac {1}{2} \, a^{5} x^{2} \mathrm {sgn}\left (b x + a\right ) - \frac {a^{7} \mathrm {sgn}\left (b x + a\right )}{42 \, b^{2}} \]
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Timed out. \[ \int x \left (a^2+2 a b x+b^2 x^2\right )^{5/2} \, dx=\int x\,{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{5/2} \,d x \]
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